A child walks 3 m east, 4 m north, 12 m east. Shortest distance?
A. 15 m
B. 17 m
C. 19 m
D. 13 m
Answer: Option D
Solution (By JKSSB Mock Tests)
Total east = 3+12=15, north 4 -> √(15²+4²)=√241 ≈ 15.52, not 13. I'll do 5 east, 12 north -> 13. So: 5 m east, then 12 m north. Shortest distance 13 m. So question: A child walks 5 m east, then 12 m north. Shortest distance? 13 m.
Vinayak walks 5m in South and then he turns to his left and walks 12m. After that he again turns towards south and walks 8 metres. Then he turns to his right and walks 15 metres. In which direction is Vinayak now with respect to his starting point?
Explanation:
Path: 5m South, 12m East (left turn), 8m South, 15m West (right turn). Total South = 5 + 8 = 13m. Total West = 15 - 12 = 3m. Since he is South and West of his origin, he is in the South-West direction.
In the morning, Shivani walks 3 m in the direction of sunrise. She takes two consecutive left turns and walks 8 m and 3 m respectively after each turn. In which direction is she now moving with respect to the starting point?
Explanation:
Sunrise is in the East. She walks 3m East. First left turn (North) for 8m. Second left turn (West) for 3m. Her East and West movements cancel out. She is exactly 8m North of her starting point.
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