A man faces north. He turns 90° left, then 180° right. Which direction? MCQ with Answer and Explanation

Explanation:
Let P be (0,0). Q is (0,-12). R is West of P, so R is (x, 0). Distance R to Q is 13. By Pythagoras, x² + (-12)² = 13² -> x² + 144 = 169 -> x² = 25 -> x = -5 (West). So R is at (-5, 0). S is 24km South of R, so S is at (-5, -24). Distance from Q(0,-12) to S(-5,-24) -> Δx = -5, Δy = -12. Distance = √((-5)² + (-12)²) = 13km. S is West and South of Q

Explanation:
West 20 m. Left (South) 40 m. Left (East) 20 m. She is back on the initial vertical line but 40 m South. Then right (South) 20 m. Total distance is 40 + 20 = 60 m South.

Explanation:
Main door faces north, so back door faces south. Path: 25 m south, left (east) 36 m, left (north) 47 m, left (west) 36 m. Net displacement: north 47 - south 25 = 22 m north; east 36 - west 36 = 0. So he is 22 m north of his house.