A man walks 4 km west, 3 km north, 12 km east. Shortest distance from start? MCQ with Answer and Explanation

Explanation:
Based on standard interpretations of this spatial puzzle, the line connecting A and B is the North-West/South-East axis. If D is on the line continuing from A through B (DA), D is situated to the North-West of A.

Explanation:
He goes 5 m North, 10 m West, 20 m North, and 10 m East. His East-West movements cancel out. Total North distance = 5 m + 20 m = 25 m.

Explanation:
Let P be (0,0). Q is (0,-12). R is West of P, so R is (x, 0). Distance R to Q is 13. By Pythagoras, x² + (-12)² = 13² -> x² + 144 = 169 -> x² = 25 -> x = -5 (West). So R is at (-5, 0). S is 24km South of R, so S is at (-5, -24). Distance from Q(0,-12) to S(-5,-24) -> Δx = -5, Δy = -12. Distance = √((-5)² + (-12)²) = 13km. S is West and South of Q