A sum of money placed at compound interest becomes double of itself in 7 years. In how many years will it become 16 times of itself? MCQ with Answer and Explanation

A sum of money placed at compound interest becomes double of itself in 7 years. In how many years will it become 16 times of itself?
A. 28 years
B. 42 years
C. 21 years
D. 35 years
Answer: Option A
Solution (By JKSSB Mock Tests)
The sum becomes 2^1 times in 7 years. It will become 16 (2^4) times in 4 * 7 = 28 years.

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Practice More Compound Interest Questions

Question #1
The difference between simple and compound interest on a sum of money for 2 years at 10% per annum is Rs. 65. Find the sum.
A. Rs. 6500
B. Rs. 7000
C. Rs. 7500
D. Rs. 6000

Correct Answer: Option A


Explanation:
Difference for 2 years = P * (R/100)^2 => 65 = P * (10/100)^2 => 65 = P * 0.01 => P = 65 / 0.01 = Rs. 6500.

This question belongs to: Maths Compound Interest
Question #2
Find the compound interest on Rs. 50000 for 1 year at 12% per annum, compounded quarterly.
A. Rs. 6520.50
B. Rs. 6400.00
C. Rs. 6000.00
D. Rs. 6275.44

Correct Answer: Option D


Explanation:
Quarterly rate = 12 / 4 = 3%. Time = 4 quarters. Amount = 50000 * (1 + 3/100)^4 = 50000 * (1.03)^4 = 50000 * 1.12550881 = Rs. 56275.44. Compound Interest = 56275.44 - 50000 = Rs. 6275.44.

This question belongs to: Maths Compound Interest
Question #3
A sum of money at compound interest doubles in 15 years. In how many years will it become 128 times?
A. 105 years
B. 120 years
C. 90 years
D. 75 years

Correct Answer: Option A


Explanation:
128 = 2⁷, so 15 × 7 = 105 years.

This question belongs to: Maths Compound Interest