If P(A)=0.2 and P(B)=0.3, the minimum possible value of P(A∪B) is: MCQ with Answer and Explanation

If P(A)=0.2 and P(B)=0.3, the minimum possible value of P(A∪B) is:
A. 0.1
B. 0.3
C. 0.5
D. 0.2
Answer: Option B
Solution (By JKSSB Mock Tests)
Minimum occurs when one event is subset of the other; if B⊂A, then P(A∪B)=P(A)=0.2. But A cannot be larger than B? Actually min union is max(P(A),P(B)) = 0.3.

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