JKSSB Mock Tests

The bond angle in a water molecule is approximately 104.5 degrees instead of 109.5 degrees due to:

A. lone pair-lone pair repulsion
B. bond pair-bond pair repulsion
C. high electronegativity of oxygen
D. hydrogen bonding
Answer: Option A
Solution (By JKSSB Mock Tests Team)
According to VSEPR theory, lone pair-lone pair repulsion is stronger than bond pair repulsion, compressing the H-O-H angle.
This Question Belongs to: General science Chemistry set 1
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