The compound interest on a sum for 3 years at 5% is Rs. 788.125. The sum is: MCQ with Answer and Explanation

The compound interest on a sum for 3 years at 5% is Rs. 788.125. The sum is:
A. Rs. 6000
B. Rs. 4500
C. Rs. 5000
D. Rs. 5500
Answer: Option C
Solution (By JKSSB Mock Tests)
CI = P[(1.05)³ − 1] = P × 0.157625 = 788.125 ⇒ P = 788.125 / 0.157625 = 5000.

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Practice More Compound Interest Questions

Question #1
The difference between compound interest (compounded annually) and simple interest on a certain sum of money for 3 years at 5% per annum is Rs. 122. Find the sum.
A. Rs. 18000
B. Rs. 15000
C. Rs. 16000
D. Rs. 17000

Correct Answer: Option C


Explanation:
Difference for 3 years = P * (R/100)^2 * (3 + R/100) => 122 = P * (5/100)^2 * (3 + 5/100) => 122 = P * (1/400) * (3.05) => 122 = P * (3.05 / 400) => P = (122 * 400) / 3.05 = 48800 / 3.05 = Rs. 16000.

This question belongs to: Maths Compound Interest
Question #2
Find the compound interest on Rs. 20000 for 1 year at 8% per annum, compounded quarterly.
A. Rs. 1600.00
B. Rs. 1680.00
C. Rs. 1648.64
D. Rs. 1712.30

Correct Answer: Option C


Explanation:
Quarterly rate = 8 / 4 = 2%. Time = 4 quarters. Amount = 20000 * (1 + 2/100)^4 = 20000 * (1.02)^4 = 20000 * 1.08243216 = Rs. 21648.64. Compound Interest = 21648.64 - 20000 = Rs. 1648.64.

This question belongs to: Maths Compound Interest
Question #3
The compound interest on a sum for 1 year at 10% compounded half-yearly is Rs. 102.50. The sum is:
A. Rs. 1100
B. Rs. 1000
C. Rs. 950
D. Rs. 1050

Correct Answer: Option B


Explanation:
A = P(1.05)² = 1.1025P, CI = 0.1025P = 102.50 ⇒ P = 1000.

This question belongs to: Maths Compound Interest