The difference between CI and SI on Rs. 4100 for 2 years at 5% is: MCQ with Answer and Explanation

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The difference between CI and SI on Rs. 4100 for 2 years at 5% is:

A. Rs. 10.25

B. Rs. 11.00

C. Rs. 8.50

D. Rs. 9.50

Answer: Option A

Solution (By JKSSB Mock Tests)

D = 4100 × 0.0025 = Rs. 10.25.

This question belongs to: Maths Compound Interest

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Question #1

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A machine depreciates at 10% per annum. Its present value is Rs. 7290. What was its value 3 years ago?

A. Rs. 10000

B. Rs. 12000

C. Rs. 11000

D. Rs. 13000

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Correct Answer: Option A

Explanation:
Value 3 years ago = 7290 / (0.9)³ = 7290 / 0.729 = 10000.

This question belongs to: Maths Compound Interest

Question #2

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The compound interest on a sum for 2 years at 8% per annum is Rs. 332.80. Find the sum.

A. Rs. 2000

B. Rs. 2100

C. Rs. 1900

D. Rs. 2200

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Correct Answer: Option A

Explanation:
CI = P[(1.08)² − 1] = P × 0.1664 = 332.80 ⇒ P = 332.80 / 0.1664 = 2000.

This question belongs to: Maths Compound Interest

Question #3

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The compound interest on Rs. 12000 for 9 months at 20% per annum, compounded quarterly, is:

A. Rs. 1891.50

B. Rs. 1800

C. Rs. 1951

D. Rs. 1900

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Correct Answer: Option A

Explanation:
Quarterly rate = 20/4 = 5%. Time = 9 months = 3 quarters. Amount = 12000 * (1 + 5/100)^3 = 12000 * (1.05)^3 = 12000 * 1.157625 = Rs. 13891.50. Compound Interest = 13891.50 - 12000 = Rs. 1891.50.

This question belongs to: Maths Compound Interest

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