The difference between CI and SI on Rs. 6400 for 2 years at 6.25% is: MCQ with Answer and Explanation

Question

Share Report Error

The difference between CI and SI on Rs. 6400 for 2 years at 6.25% is:

A. Rs. 25

B. Rs. 30

C. Rs. 35

D. Rs. 20

Answer: Option A

Solution (By JKSSB Mock Tests)

6.25% = 1/16. D = P × (R/100)² = 6400 × (1/16)² = 6400 × 1/256 = Rs. 25.

This question belongs to: Maths Compound Interest

Request complete Subject PDF

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Compound Interest Questions

Question #1

Share Report

The difference between simple interest and compound interest on a certain sum of money for 3 years at 10% per annum is Rs. 186. Find the sum.

A. Rs. 5500

B. Rs. 6500

C. Rs. 6000

D. Rs. 7000

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option C

Explanation:
Difference for 3 years = P * (R/100)^2 * (3 + R/100) => 186 = P * (10/100)^2 * (3 + 10/100) => 186 = P * (1/100) * (3.1) => 186 = P * 0.031 => P = 186 / 0.031 = Rs. 6000.

This question belongs to: Maths Compound Interest

Question #2

Share Report

The compound interest on a sum for 2 years at 5% is Rs. 205. Find the sum.

A. Rs. 2100

B. Rs. 2000

C. Rs. 1900

D. Rs. 2200

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option B

Explanation:
CI = P[(1.05)² − 1] = P × 0.1025 = 205 ⇒ P = 2000.

This question belongs to: Maths Compound Interest

Question #3

Share Report

The value of a machine depreciates at the rate of 10% per annum. If its present value is Rs. 162000, what was its value 2 years ago?

A. Rs. 210000

B. Rs. 190000

C. Rs. 200000

D. Rs. 220000

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option C

Explanation:
Value 2 years ago = 162000 / (1 - 10/100)^2 = 162000 / (0.9)^2 = 162000 / 0.81 = Rs. 200000.

This question belongs to: Maths Compound Interest

Explore All Compound Interest MCQs