The difference between simple interest and compound interest on a certain sum of money for 3 years at 10% per annum is Rs. 217. Find the sum. MCQ with Answer and Explanation

The difference between simple interest and compound interest on a certain sum of money for 3 years at 10% per annum is Rs. 217. Find the sum.
A. Rs. 7500
B. Rs. 8000
C. Rs. 6500
D. Rs. 7000
Answer: Option D
Solution (By JKSSB Mock Tests)
Difference for 3 years = P * (R/100)^2 * (3 + R/100) => 217 = P * (10/100)^2 * (3 + 10/100) => 217 = P * (1/100) * (3.1) => 217 = P * 0.031 => P = 217 / 0.031 = Rs. 7000.

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Practice More Compound Interest Questions

Question #1
A sum of money at compound interest becomes 9 times in 4 years. In how many years will it become 81 times?
A. 10 years
B. 6 years
C. 7 years
D. 8 years

Correct Answer: Option D


Explanation:
81 = 9², so 4 × 2 = 8 years.

This question belongs to: Maths Compound Interest
Question #2
A sum of money invested at compound interest doubles itself in 19 years. In how many years will it become 4 times of itself?
A. 48 years
B. 38 years
C. 28 years
D. 58 years

Correct Answer: Option B


Explanation:
The sum doubles (2^1) in 19 years. It will become 4 (2^2) times in 2 * 19 = 38 years.

This question belongs to: Maths Compound Interest
Question #3
The compound interest on Rs. 5000 at 8% per annum for 1 year compounded half-yearly is:
A. Rs. 400
B. Rs. 412
C. Rs. 408
D. Rs. 416

Correct Answer: Option C


Explanation:
Rate per half-year = 4%, n = 2. A = 5000 × (1.04)² = 5000 × 1.0816 = 5408, CI = 5408 − 5000 = Rs. 408.

This question belongs to: Maths Compound Interest