The difference between simple interest and compound interest on a certain sum of money for 3 years at 10% per annum is Rs. 217. Find the sum. MCQ with Answer and Explanation

The difference between simple interest and compound interest on a certain sum of money for 3 years at 10% per annum is Rs. 217. Find the sum.
A. Rs. 8000
B. Rs. 6500
C. Rs. 7500
D. Rs. 7000
Answer: Option D
Solution (By JKSSB Mock Tests)
Difference for 3 years = P * (R/100)^2 * (3 + R/100) => 217 = P * (10/100)^2 * (3 + 10/100) => 217 = P * (1/100) * (3.1) => 217 = P * 0.031 => P = 217 / 0.031 = Rs. 7000.

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Practice More Compound Interest Questions

Question #1
The simple interest on a sum at 5% for 3 years is Rs. 600. The compound interest on the same sum for 2 years at 5% is:
A. Rs. 400
B. Rs. 415
C. Rs. 405
D. Rs. 410

Correct Answer: Option D


Explanation:
P = 60000/(5×3) = 4000. CI = 4000[(1.05)² − 1] = 4000 × 0.1025 = Rs. 410.

This question belongs to: Maths Compound Interest
Question #2
The difference between simple interest and compound interest on a certain sum of money for 3 years at 10% per annum is Rs. 930. Find the sum.
A. Rs. 34000
B. Rs. 30000
C. Rs. 28000
D. Rs. 32000

Correct Answer: Option B


Explanation:
Difference for 3 years = P * (R/100)^2 * (3 + R/100) => 930 = P * (10/100)^2 * (3 + 10/100) => 930 = P * (1/100) * (3.1) => 930 = P * 0.031 => P = 930 / 0.031 = Rs. 30000.

This question belongs to: Maths Compound Interest
Question #3
A sum of money placed at compound interest becomes double of itself in 4 years. In how many years will it become 32 times of itself?
A. 16 years
B. 28 years
C. 20 years
D. 24 years

Correct Answer: Option C


Explanation:
The sum becomes 2^1 times in 4 years. It will become 32 (2^5) times in 5 * 4 = 20 years.

This question belongs to: Maths Compound Interest