The population of a town increases at 10% per annum. If the present population is 20000, what will it be after 2 years? MCQ with Answer and Explanation

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The population of a town increases at 10% per annum. If the present population is 20000, what will it be after 2 years?

A. 24200

B. 24000

C. 24400

D. 24600

Answer: Option A

Solution (By JKSSB Mock Tests)

Population = 20000 × (1.1)² = 20000 × 1.21 = 24200.

This question belongs to: Maths Compound Interest

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Question #1

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The simple interest on a sum for 2 years at 4% is Rs. 200. The compound interest on the same sum for 2 years at 4% is:

A. Rs. 202

B. Rs. 200

C. Rs. 204

D. Rs. 206

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Correct Answer: Option C

Explanation:
P = 20000/(4×2) = 2500. CI = 2500 × [(1.04)² − 1] = 2500 × 0.0816 = 204.

This question belongs to: Maths Compound Interest

Question #2

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The simple interest on a sum for 3 years at 10% is Rs. 900. The compound interest on the same sum for 2 years at 10% is:

A. Rs. 660

B. Rs. 690

C. Rs. 630

D. Rs. 600

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Correct Answer: Option C

Explanation:
P = 90000/(10×3) = 3000. CI = 3000 × 0.21 = 630.

This question belongs to: Maths Compound Interest

Question #3

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The difference between simple interest and compound interest on Rs. 18000 for 2 years is Rs. 405. Find the rate of interest per annum.

A. 15%

B. 20%

C. 12%

D. 18%

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Correct Answer: Option A

Explanation:
Difference for 2 years = P * (R/100)^2 => 405 = 18000 * (R/100)^2 => 405 = 1.8 * R^2 => R^2 = 405 / 1.8 = 225 => R = 15%.

This question belongs to: Maths Compound Interest

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