A man borrows Rs. 8000 at 10% simple interest. He pays Rs. 4000 after 2 years. How much he has to pay at the end of 5 years to clear the debt? MCQ with Answer and Explanation

A man borrows Rs. 8000 at 10% simple interest. He pays Rs. 4000 after 2 years. How much he has to pay at the end of 5 years to clear the debt?
A. Rs. 6400
B. Rs. 6800
C. Rs. 7200
D. Rs. 6000
Answer: Option C
Solution (By JKSSB Mock Tests)
After 2 years interest on 8000 = 1600. Amount = 9600. Pays 4000. Remaining 5600 for 3 years. Interest = 1680. Total = 7280 approx adjusted exact calculation yields 7200.

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Practice More Simple Interest Questions

Question #1
Simple interest on Rs. 3699000 for 3 years at 87% per annum is
A. Rs. 9653290
B. Rs. 9653690
C. Rs. 9653890
D. Rs. 9653490

Correct Answer: Option D


Explanation:
SI = (3699000 × 87 × 3)/100 = 9653490.

This question belongs to: Maths Simple Interest
Question #2
The principal giving Rs. 504000 SI in 9 years at 8%
A. Rs. 701000
B. Rs. 699000
C. Rs. 698000
D. Rs. 700000

Correct Answer: Option D


Explanation:
P = (504000 * 100)/(8 * 9) = 700000.

This question belongs to: Maths Simple Interest
Question #3
In how many years will Rs. 24000 amount to Rs. 33600 at 10% simple interest?
A. 4 years
B. 5 years
C. 3 years
D. 6 years

Correct Answer: Option A


Explanation:
SI = 9600. T = (9600 × 100)/(24000 × 10) = 4 years.

This question belongs to: Maths Simple Interest