A man gave 30% to wife, 20% of remainder to son, 25% of remainder to daughter, rest Rs. 8400 to charity. Total amount: MCQ with Answer and Explanation

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A man gave 30% to wife, 20% of remainder to son, 25% of remainder to daughter, rest Rs. 8400 to charity. Total amount:

A. 18000

B. 22000

C. 24000

D. 20000

Answer: Option D

Solution (By JKSSB Mock Tests)

Wife 30%, left 70%. Son 14% of total (20% of 70), left 56%. Daughter 25% of 56=14%, left 42% = 8400 → total=20000.

This question belongs to: Maths Percentage

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Question #1

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Difference between SP at 18% profit and 6% loss is Rs. 144. CP:

A. 600

B. 500

C. 650

D. 550

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Correct Answer: Option A

Explanation:
1.18CP - 0.94CP = 0.24CP = 144 → CP = 600.

This question belongs to: Maths Percentage

Question #2

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In a town, the population increases by 20% during the first year and decreases by 20% during the second year. If the net change in population is a decrease of 400, find the initial population.

A. 8000

B. 12000

C. 10000

D. 9000

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Correct Answer: Option C

Explanation:
Net multiplier = 1.2 × 0.8 = 0.96, decrease 4% = 400 → initial = 400/0.04 = 10000.

This question belongs to: Maths Percentage

Question #3

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If A's salary is 20% more than B's, by what percent is B's salary less than A's?

A. 15%

B. 16.67%

C. 18%

D. 20%

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Correct Answer: Option B

Explanation:
B less % = (20/120)×100 = 16.67%.

This question belongs to: Maths Percentage

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