A man gave 30% to wife, 20% of remainder to son, 25% of remainder to daughter, rest Rs. 8400 to charity. Total amount: MCQ with Answer and Explanation

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A man gave 30% to wife, 20% of remainder to son, 25% of remainder to daughter, rest Rs. 8400 to charity. Total amount:

A. 24000

B. 18000

C. 20000

D. 22000

Answer: Option C

Solution (By JKSSB Mock Tests)

Wife 30%, left 70%. Son 14% of total (20% of 70), left 56%. Daughter 25% of 56=14%, left 42% = 8400 → total=20000.

This question belongs to: Maths Percentage

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Question #1

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The population of a town increases by 8% annually. If its present population is 2,33,280, what was it 2 years ago?

A. 2,00,000

B. 1,80,000

C. 1,90,000

D. 2,10,000

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Correct Answer: Option A

Explanation:
Pop 2 yrs ago = 233280 / (1.08)² = 233280 / 1.1664 = 200000.

This question belongs to: Maths Percentage

Question #2

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If 15 men can complete a work in 20 days, how many men are required to complete the work in 10 days?

A. 30

B. 28

C. 25

D. 32

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Correct Answer: Option A

Explanation:
M1×D1 = M2×D2 → 15×20 = M2×10 → M2 = 30.

This question belongs to: Maths Percentage

Question #3

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A's income is 25% more than B's. B's expenditure is 40% less than A's. If A saves 20% of his income, what percent does B save?

A. 30%

B. 35%

C. 45%

D. 40%

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Correct Answer: Option D

Explanation:
Let B inc=100, A=125. A sav=25, A exp=100. B exp=0.6×100=60, B sav=100-60=40, i.e. 40%.

This question belongs to: Maths Percentage

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