A person walks 20 m in the east. Walked and turned 90° clockwise and walked 20 m. walked. From there he again turns to his left and walks 10 m. Then he turned 90° anticlockwise and walked 20 m. walked. How far and in which direction is he from the starting point? MCQ with Answer and Explanation
A person walks 20 m in the east. Walked and turned 90° clockwise and walked 20 m. walked. From there he again turns to his left and walks 10 m. Then he turned 90° anticlockwise and walked 20 m. walked. How far and in which direction is he from the starting point?
A. 30 m. South
B. 25 m. East
C. 30 m. North
D. 30 m. East
Answer: Option D
Solution (By JKSSB Mock Tests)
Walks 20 m East. Turns 90° CW (South) for 20 m. Turns left (East) for 10 m. Turns 90° CCW (North) for 20 m. The 20 m South and 20 m North cancel each other. Total horizontal distance = 20 m East + 10 m East = 30 m East.
Sahil walks 5 km towards north from a fixed point. Then he turns right and walks 3 km. After this he turns right and walks 5 km. Finally he turns left and walks 4 km. Now in which direction and at what distance is he from the fixed position?
Explanation:
Sahil goes 5 km North, then 3 km East, then 5 km South (back to the original horizontal line), and finally 4 km East. Total distance from the start is 3 km + 4 km = 7 km. He is to the East of his starting point.
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