A ship sails 10 km east, then 10 km south, then 10 km west. How far is it from start? MCQ with Answer and Explanation

Explanation:
Let clockwise turns be positive and anticlockwise be negative. Total turn = +90° - 180° - 135° + 180° = -45° (which means 45° anticlockwise). Her final direction is North-East. If she arrived at North-East after a 45° anticlockwise turn, her initial direction must have been East.

Explanation:
Net 10 km east.

Explanation:
Net east = 8-2 = 6 km, north = 6 km. Distance = √(6²+6²)=√72=6√2 ≈ 8.48. Not option. I'll adjust: East 8, north 6, west 4 => net east 4, north 6 => √52. Not. Let's do: 6 km east, 8 km north, then 6 km west? That's net north 8. So distance 8. I'll make: 6 east, 8 north, 2 west: net east 4, north 8 => √(16+64)=√80. Not nice. I'll set: 8 km east, 6 km north, then 8 km west -> net north 6. So distance 6. But then distance 6, option? I'll use 6 km east, 8 km north, 6 km west -> net north 8. So distance 8 km. Option D 8 km. That works.