A sum of money invested at compound interest doubles itself in 5 years. In how many years will it become 8 times of itself? MCQ with Answer and Explanation

A sum of money invested at compound interest doubles itself in 5 years. In how many years will it become 8 times of itself?
A. 15 years
B. 20 years
C. 10 years
D. 25 years
Answer: Option A
Solution (By JKSSB Mock Tests)
The sum doubles (2^1) in 5 years. It will become 8 (2^3) times in 3 * 5 = 15 years.

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Practice More Compound Interest Questions

Question #1
The difference between simple interest and compound interest on a certain sum of money for 3 years at 10% per annum is Rs. 186. Find the sum.
A. Rs. 6000
B. Rs. 7000
C. Rs. 6500
D. Rs. 5500

Correct Answer: Option A


Explanation:
Difference for 3 years = P * (R/100)^2 * (3 + R/100) => 186 = P * (10/100)^2 * (3 + 10/100) => 186 = P * (1/100) * (3.1) => 186 = P * 0.031 => P = 186 / 0.031 = Rs. 6000.

This question belongs to: Maths Compound Interest
Question #2
A sum of money invested at compound interest doubles itself in 9 years. In how many years will it become 8 times of itself?
A. 36 years
B. 18 years
C. 45 years
D. 27 years

Correct Answer: Option D


Explanation:
The sum doubles (2^1) in 9 years. It will become 8 (2^3) times in 3 * 9 = 27 years.

This question belongs to: Maths Compound Interest
Question #3
The compound interest on Rs. 16000 at 10% per annum for 1.5 years compounded half-yearly is:
A. Rs. 2522
B. Rs. 2600
C. Rs. 2400
D. Rs. 2662

Correct Answer: Option A


Explanation:
Half-yearly rate 5%, n=3. A = 16000 × (1.05)³ = 16000 × 1.157625 = 18522, CI = 18522 − 16000 = 2522.

This question belongs to: Maths Compound Interest