A sum of money placed at compound interest becomes double of itself in 10 years. In how many years will it become 8 times of itself? MCQ with Answer and Explanation

A sum of money placed at compound interest becomes double of itself in 10 years. In how many years will it become 8 times of itself?
A. 50 years
B. 30 years
C. 20 years
D. 40 years
Answer: Option B
Solution (By JKSSB Mock Tests)
The sum becomes 2^1 times in 10 years. It will become 8 (2^3) times in 3 * 10 = 30 years.

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Practice More Compound Interest Questions

Question #1
A sum of money yields a compound interest of Rs. 205 in 2 years at 5% per annum. Find the principal sum.
A. Rs. 2200
B. Rs. 1800
C. Rs. 2000
D. Rs. 2400

Correct Answer: Option C


Explanation:
Effective rate of compound interest for 2 years at 5% = 5 + 5 + (55)/100 = 10.25%. Given 10.25% of P = 205 => P = 205 / 0.1025 = Rs. 2000.

This question belongs to: Maths Compound Interest
Question #2
What is the compound interest on Rs. 16000 for 1.5 years at 10% per annum, compounded half-yearly?
A. Rs. 2600
B. Rs. 2522
C. Rs. 2520
D. Rs. 2400

Correct Answer: Option B


Explanation:
Half-yearly rate = 10/2 = 5%. Time = 1.5 years = 3 half-years. Amount = 16000 * (1 + 5/100)^3 = 16000 * (1.05)^3 = 16000 * 1.157625 = Rs. 18522. Compound Interest = 18522 - 16000 = Rs. 2522.

This question belongs to: Maths Compound Interest
Question #3
At compound interest, a sum becomes 1.21 times in 2 years. The rate of interest per annum is:
A. 9%
B. 11%
C. 10%
D. 12%

Correct Answer: Option C


Explanation:
(1 + r)² = 1.21 ⇒ 1 + r = 1.1 ⇒ r = 10%.

This question belongs to: Maths Compound Interest