A town's population increases by 10% in the first year and 20% in the second year. What is the net percentage increase? MCQ with Answer and Explanation

A town's population increases by 10% in the first year and 20% in the second year. What is the net percentage increase?
A. 32%
B. 30%
C. 35%
D. 33%
Answer: Option A
Solution (By JKSSB Mock Tests)
Net change = 10 + 20 + ((10 * 20) / 100) = 30 + 2 = 32%.

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Practice More Percentage Questions

Question #1
A person spends 25% of his income on food, 20% on rent, 15% on education and saves the rest. If his savings are Rs. 7200, his income is:
A. Rs. 15000
B. Rs. 18000
C. Rs. 16000
D. Rs. 20000

Correct Answer: Option B


Explanation:
Spend % = 25+20+15=60%, save 40% = 7200, income = 7200/0.4 = 18000.

This question belongs to: Maths Percentage
Question #2
25% reduction in sugar price lets a person buy 8 kg more for Rs. 200. Reduced price per kg:
A. Rs. 5
B. Rs. 6
C. Rs. 5.5
D. Rs. 6.25

Correct Answer: Option D


Explanation:
Original price x, consumption y, xy=200. New 0.75x(y+8)=200 → 150 + 6x = 200 → 6x=50 → x=25/3≈8.33, reduced price 0.75*x = 6.25. So Rs. 6.25.

This question belongs to: Maths Percentage
Question #3
Two successive increases of 20% and 20% on a price is equivalent to a single increase of:
A. 46%
B. 42%
C. 40%
D. 44%

Correct Answer: Option D


Explanation:
1.2 × 1.2 = 1.44, increase 44%.

This question belongs to: Maths Percentage