A walks 10 metres in front and 10 metres to the right. Then every time turning to his left, he walks 5, 15 and 15 metres respectively. How far is he now from his starting point? MCQ with Answer and Explanation

A walks 10 metres in front and 10 metres to the right. Then every time turning to his left, he walks 5, 15 and 15 metres respectively. How far is he now from his starting point?
A. 10 metres
B. 20 metres
C. 5 metres
D. 15 metres
Answer: Option C
Solution (By JKSSB Mock Tests)
Assume start facing North 10 m. Right (East) 10 m. Left (North) 5 m. Left (West) 15 m. Left (South) 15 m. Net: North 10+5−15=0, East 10−15=−5 (5 m West). Distance 5 m.

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Practice More Mental Reasoning Questions

Question #1
If in a certain language, 'MADRAS' is coded as 'NBESBT', how is 'BOMBAY' coded in that language?
A. CPNCBZ
B. CQOCBZ
C. CPNCBX
D. CPOCBZ

Correct Answer: Option A


Explanation:
Each letter is increased by 1. M→N, A→B, D→E, R→S, A→B, S→T. Similarly B→C, O→P, M→N, B→C, A→B, Y→Z. Thus BOMBAY becomes CPNCBZ.

This question belongs to: Reasoning Mental Reasoning
Question #2
Find the odd one out: 2, 3, 5, 7, 9
A. 2
B. 9
C. 7
D. 3

Correct Answer: Option B


Explanation:
9 is composite, while 2, 3, 5 and 7 are prime numbers.

This question belongs to: Reasoning Mental Reasoning
Question #3
Find the missing term: 80, 40, 20, 10, ?
A. 8
B. 4
C. 2
D. 5

Correct Answer: Option D


Explanation:
Each term is divided by 2: 80÷2=40, 40÷2=20, 20÷2=10, so next is 10÷2=5.

This question belongs to: Reasoning Mental Reasoning