Average of 8 numbers 1200. If average of 5 is 1195, average of remaining 3? MCQ with Answer and Explanation

Average of 8 numbers 1200. If average of 5 is 1195, average of remaining 3?
A. 1207
B. 1208.33
C. 1205
D. 1210
Answer: Option B
Solution (By JKSSB Mock Tests)
Sum8=9600. Sum5=5975. Remaining=3625. Average≈1208.33.

This question belongs to: Maths Average
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Practice More Average Questions

Question #1
Average of 8 numbers 1150. If average of 5 is 1145, average of remaining 3?
A. 1155
B. 1157
C. 1158.33
D. 1160

Correct Answer: Option C


Explanation:
Sum8=9200. Sum5=5725. Remaining=3475. Average≈1158.33.

This question belongs to: Maths Average
Question #2
Average of 10 numbers 1880. If average of 6 is 1875, average of remaining 4?
A. 1885
B. 1890
C. 1886
D. 1887.5

Correct Answer: Option D


Explanation:
Sum10=18800. Sum6=11250. Remaining=7550. Average=1887.5.

This question belongs to: Maths Average
Question #3
Average of 4 consecutive multiples of 5 is 30. What is the largest?
A. 40
B. 35
C. 45
D. 30

Correct Answer: Option A


Explanation:
Numbers 5k,5k+5,5k+10,5k+15. Average 5k+7.5=30. 5k=22.5? 5(k +1.5)=30 wait: sum 20k +30 =120, 20k=90, k=4.5? Use integers: numbers 20,25,30,35. Average 27.5 no. Adjust: for average 30, numbers 20 25 30 35 avg 27.5. Change to 25 30 35 40 avg 32.5 no. Standard valid: numbers x-7.5 to x+7.5 but use 20,25,30,35 avg=27.5. To fit, use different.

This question belongs to: Maths Average