Average of 8 numbers 2100. If average of 5 is 2095, average of remaining 3? MCQ with Answer and Explanation

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Average of 8 numbers 2100. If average of 5 is 2095, average of remaining 3?

A. 2105

B. 2108.33

C. 2107

D. 2110

Answer: Option B

Solution (By JKSSB Mock Tests)

Sum8=16800. Sum5=10475. Remaining=6325. Average≈2108.33.

This question belongs to: Maths Average

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Question #1

Average of 25 numbers 85. If average of 15 is 90, average of remaining 10?

A. 80

B. 77.5

C. 75

D. 78

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Correct Answer: Option B

Explanation:
Total=2125. Sum15=1350. Remaining=775/10=77.5.

This question belongs to: Maths Average

Question #2

The average of 6 numbers is 28. If each is increased by 50%, new average?

A. 42

B. 28

C. 35

D. 40

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Correct Answer: Option A

Explanation:
Increased by 50%, average 28*1.5=42.

This question belongs to: Maths Average

Question #3

The average of 9 numbers is 42. If each number is decreased by 6, what is the new average?

A. 36

B. 42

C. 30

D. 48

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Correct Answer: Option A

Explanation:
New average =42-6=36.

This question belongs to: Maths Average

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