Average of 9 numbers 1840. If average of 6 is 1835, average of remaining 3? MCQ with Answer and Explanation

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Average of 9 numbers 1840. If average of 6 is 1835, average of remaining 3?

A. 1848

B. 1850

C. 1855

D. 1845

Answer: Option B

Solution (By JKSSB Mock Tests)

Sum9=16560. Sum6=11010. Remaining=5550. Average=1850.

This question belongs to: Maths Average

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Question #1

Average of 8 numbers 1700. If average of 5 is 1695, average of remaining 3?

A. 1710

B. 1708.33

C. 1707

D. 1705

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Correct Answer: Option B

Explanation:
Sum8=13600. Sum5=8475. Remaining=5125. Average≈1708.33.

This question belongs to: Maths Average

Question #2

The average of 5 numbers is 40. If each number is decreased by 5, what is the new average?

A. 30

B. 40

C. 45

D. 35

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Correct Answer: Option D

Explanation:
If each number is decreased by a constant, the average also decreases by that constant. New average =40-5=35.

This question belongs to: Maths Average

Question #3

The average of 1110,1480,1850 is

A. 1490

B. 1475

C. 1480

D. 1470

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Correct Answer: Option C

Explanation:
4440/3=1480.

This question belongs to: Maths Average

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