Average of 9 numbers 1840. If average of 6 is 1835, average of remaining 3? MCQ with Answer and Explanation

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Average of 9 numbers 1840. If average of 6 is 1835, average of remaining 3?

A. 1845

B. 1850

C. 1848

D. 1855

Answer: Option B

Solution (By JKSSB Mock Tests)

Sum9=16560. Sum6=11010. Remaining=5550. Average=1850.

This question belongs to: Maths Average

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Question #1

The average of 5 numbers is 24. If two numbers 18 and 30 are excluded, average of remaining?

A. 22

B. 24

C. 26

D. 25

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Correct Answer: Option B

Explanation:
Sum5=120. Remaining sum=120-48=72. Average=72/3=24.

This question belongs to: Maths Average

Question #2

Average of 5 consecutive odd numbers is 27. Largest?

A. 35

B. 33

C. 31

D. 29

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Correct Answer: Option C

Explanation:
Largest=27+4=31.

This question belongs to: Maths Average

Question #3

Average of 645,860,1075 is

A. 870

B. 850

C. 855

D. 860

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Correct Answer: Option D

Explanation:
2580/3=860.

This question belongs to: Maths Average

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