Bleaching powder (CaOCl₂) releases chlorine when treated with: MCQ with Answer and Explanation

Bleaching powder (CaOCl₂) releases chlorine when treated with:
A. Water only
B. Ammonia
C. Dilute acids
D. Sodium hydroxide
Answer: Option C
Solution (By JKSSB Mock Tests)
CaOCl₂ + 2HCl (dil.) → CaCl₂ + Cl₂ + H₂O. It also releases Cl₂ on reaction with CO₂ in air: CaOCl₂ + CO₂ → CaCO₃ + Cl₂. Water alone hydrolyses it slowly. NaOH does not release Cl₂. The chlorine gas is responsible for bleaching and disinfection.

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Question #1
Which of the following is a metalloid?
A. Sodium
B. Calcium
C. Oxygen
D. Arsenic

Correct Answer: Option D


Explanation:
Arsenic (As) is a metalloid, showing properties of both metals and non-metals. It is in group 15, period 4. Sodium and calcium are metals. Oxygen is a non-metal. Metalloids: B, Si, Ge, As, Sb, Te. They are semiconductors and form amphoteric oxides.

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Question #2
The bond in CO is actually a triple bond with a coordinate covalent bond. The total number of electrons shared between C and O in CO is:
A. 4
B. 8
C. 6
D. 2

Correct Answer: Option C


Explanation:
CO has a triple bond: one sigma and two pi bonds, with a coordinate covalent character where oxygen donates a lone pair to carbon, forming a bond similar to triple bond. Total shared electrons = 6 (three pairs). Lewis structure shows :C≡O: with formal charges. The bond order is 3. It is isoelectronic with N₂ and CN⁻.

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Question #3
A radioactive sample decays to 1/4 of its original amount in 40 days. Its half-life is:
A. 40 days
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C. 80 days
D. 10 days

Correct Answer: Option B


Explanation:
1/4 = (1/2)², so 2 half-lives = 40 days → half-life = 20 days. After 1 half-life 1/2 remains, after 2 half-lives 1/4.

This question belongs to: Science chemistry