Find the mean proportional between 11 and 38. MCQ with Answer and Explanation

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Find the mean proportional between 11 and 38.

A. 49

B. 23

C. 40

D. 20

Answer: Option D

Solution (By JKSSB Mock Tests)

Mean proportional = √(11 × 38) = √(418) = 20.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Two numbers are in ratio 7:4. Their difference is 73. What is their sum?

A. 594

B. 734

C. 297

D. 636

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Correct Answer: Option A

Explanation:
Numbers 7k, 4k. Difference |7-4|k = 73 ⇒ k = 24. Sum = (7+4)k ≈ 594.

This question belongs to: Maths Ratio and Proportion

Question #2

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If a:b = 8:7 and b:c = 7:6, then a:b:c = ?

A. 8:7:6

B. 16:14:12

C. 8:8:6

D. 7:7:7

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Correct Answer: Option A

Explanation:
Combine ratios: a:b = 8:7, b:c = 7:6 ⇒ a:b:c = 8:7:6.

This question belongs to: Maths Ratio and Proportion

Question #3

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Ratio of present ages of A and B is 7:8. After 11 years, the ratio becomes 10:10. Present age of A is?

A. 322 years

B. 166 years

C. 156 years

D. 161 years

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Correct Answer: Option D

Explanation:
Let ages 7k and 8k. Then (7k + 11)/(8k + 11) = 10/10. Solving gives k ≈ 23, age of A = 7*23 = 161.

This question belongs to: Maths Ratio and Proportion

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