Ratio of present ages of A and B is 7:8. After 11 years, the ratio becomes 8:9. Present age of A is? MCQ with Answer and Explanation

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Ratio of present ages of A and B is 7:8. After 11 years, the ratio becomes 8:9. Present age of A is?

A. 126 years

B. 131 years

C. 252 years

D. 119 years

Answer: Option A

Solution (By JKSSB Mock Tests)

Let ages 7k and 8k. Then (7k + 11)/(8k + 11) = 8/9. Solving gives k ≈ 18, age of A = 7*18 = 126.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Two numbers are in ratio 11:9. Their difference is 111. What is their sum?

A. 480

B. 560

C. 240

D. 526

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Correct Answer: Option A

Explanation:
Numbers 11k, 9k. Difference |11-9|k = 111 ⇒ k = 55. Sum = (11+9)k ≈ 480.

This question belongs to: Maths Ratio and Proportion

Question #2

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Ratio of present ages of A and B is 5:8. After 12 years, the ratio becomes 6:11. Present age of A is?

A. 50 years

B. 55 years

C. 60 years

D. 110 years

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Correct Answer: Option B

Explanation:
Let ages 5k and 8k. Then (5k + 12)/(8k + 12) = 6/11. Solving gives k ≈ 11, age of A = 5*11 = 55.

This question belongs to: Maths Ratio and Proportion

Question #3

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If a:b = 7:9 and b:c = 9:5, then a:b:c = ?

A. 6:9:6

B. 14:18:10

C. 7:9:5

D. 7:10:5

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Correct Answer: Option C

Explanation:
Combine ratios: a:b = 7:9, b:c = 9:5 ⇒ a:b:c = 7:9:5.

This question belongs to: Maths Ratio and Proportion

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