Find the principal that yields a compound interest of Rs. 410 in 2 years at 5% per annum. MCQ with Answer and Explanation

Find the principal that yields a compound interest of Rs. 410 in 2 years at 5% per annum.
A. Rs. 4200
B. Rs. 4000
C. Rs. 4400
D. Rs. 3800
Answer: Option B
Solution (By JKSSB Mock Tests)
CI = P[(1.05)² − 1] = P × 0.1025 = 410 ⇒ P = 410 / 0.1025 = 4000.

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Practice More Compound Interest Questions

Question #1
The difference between simple interest and compound interest on a certain sum of money for 3 years at 5% per annum is Rs. 244. Find the sum.
A. Rs. 30000
B. Rs. 32000
C. Rs. 36000
D. Rs. 34000

Correct Answer: Option B


Explanation:
Difference for 3 years = P * (R/100)^2 * (3 + R/100) => 244 = P * (5/100)^2 * (3 + 5/100) => 244 = P * (1/400) * (3.05) => P = (244 * 400) / 3.05 = 97600 / 3.05 = Rs. 32000.

This question belongs to: Maths Compound Interest
Question #2
At what rate percent per annum will Rs. 8000 amount to Rs. 8820 in 2 years, compound interest compounded annually?
A. 6%
B. 8%
C. 5%
D. 4%

Correct Answer: Option C


Explanation:
Amount/Principal = 8820 / 8000 = 882 / 800 = 441 / 400 = (21 / 20)^2. Therefore, 1 + R/100 = 21/20 => R/100 = 1/20 => R = 5%.

This question belongs to: Maths Compound Interest
Question #3
The difference between simple interest and compound interest on a certain sum of money for 3 years at 10% per annum is Rs. 93. Find the sum.
A. Rs. 3000
B. Rs. 3500
C. Rs. 2000
D. Rs. 2500

Correct Answer: Option A


Explanation:
Difference for 3 years = P * (R/100)^2 * (3 + R/100). Given 93 = P * (10/100)^2 * (3 + 10/100) => 93 = P * (1/100) * (3.1) => 93 = P * 0.031 => P = 93 / 0.031 = Rs. 3000.

This question belongs to: Maths Compound Interest