For two attributes A and B, independence (no association) implies: MCQ with Answer and Explanation

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For two attributes A and B, independence (no association) implies:

A. (AB) = 0

B. (AB) = (A) + (B)

C. (AB) = (A)(B)/N²

D. (AB)/N = (A)/N × (B)/N

Answer: Option D

Solution (By JKSSB Mock Tests)

Independence means the proportion of items with both attributes equals the product of the individual proportions.

This question belongs to: Accountancy and Statistics Statistics

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Question #1

For mutually exclusive events A and B with P(A)=0.4, P(B)=0.3, P(A∪B) is:

A. 0.1

B. 0.58

C. 0.12

D. 0.7

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Correct Answer: Option D

Explanation:
Since A and B are mutually exclusive, P(A∪B) = P(A) + P(B) = 0.7.

This question belongs to: Accountancy and Statistics Statistics

Question #2

In a well-designed questionnaire, questions on income should be:

A. Randomly placed

B. Towards the end, as they are sensitive

C. In the middle, with no introduction

D. At the beginning to motivate

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Correct Answer: Option B

Explanation:
Sensitive questions are placed later to build trust and reduce dropout.

This question belongs to: Accountancy and Statistics Statistics

Question #3

The mode of a continuous frequency distribution can be estimated using the formula:

A. L + [(f₀ - f₁) / (f₀ + f₁)] × h

B. L + [(f₁ - f₀) / (2f₁ - f₀ - f₂)] × h

C. L + [(f₁ - f₀) / (f₁ - f₂)] × h

D. L + (h / 2)

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Correct Answer: Option B

Explanation:
For grouped data, mode = L + [(f₁ - f₀) / (2f₁ - f₀ - f₂)] × h, where L=lower limit of modal class, f₁=frequency of modal class, f₀=previous class frequency, f₂=next class frequency, h=class width.

This question belongs to: Accountancy and Statistics Statistics

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