How many total octets are used to construct a standard 32-bit IPv4 network address configuration? MCQ with Answer and Explanation

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How many total octets are used to construct a standard 32-bit IPv4 network address configuration?

A. 2 octets

B. 6 octets

C. 8 octets

D. 4 octets

Answer: Option D

Solution (By JKSSB Mock Tests)

An IPv4 address contains 32 bits divided into 4 octets (8 bits each), separated by dots in decimal format.

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Question #1

What is the maximum number of hosts in a Class B network?

A. 16,777,214

B. 65,534

C. 254

D. 65,536

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Correct Answer: Option B

Explanation:
Class B has 16 host bits, giving 2^16 - 2 = 65,534 usable hosts.

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Question #2

Which address block represents the standard 32-bit IPv4 multicast address group space under traditional classful sorting hierarchies?

A. 240.0.0.0 to 255.255.255.255

B. 0.0.0.0 to 127.255.255.255

C. 224.0.0.0 to 239.255.255.255

D. 192.168.0.0 to 192.168.255.255

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Correct Answer: Option C

Explanation:
Class D addresses (224.0.0.0 to 239.255.255.255) are reserved globally for multicast traffic targeting specific groups of devices.

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Question #3

What is the purpose of a gateway in a network?

A. To filter traffic based on MAC

B. To connect networks with different protocols

C. To amplify signals

D. To assign IP addresses

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Correct Answer: Option B

Explanation:
A gateway translates between different network protocols and architectures.

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