If P(A) = 0.3, P(B) = 0.4, and A and B are independent, P(A ∪ B) is:

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For independent events, P(A∩B)=P(A)P(B)=0.3×0.4=0.12. Then P(A∪B)=P(A)+P(B)-P(A∩B)=0.3+0.4-0.12=0.58, applying the addition theorem with the independence condition.

If P(A) = 0.3, P(B) = 0.4, and A and B are independent, P(A ∪ B) is: MCQ with Answer and Explanation

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