If P(A) = 0.3, P(B) = 0.4, and A, B are mutually exclusive, then P(A∪B) is: MCQ with Answer and Explanation

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If P(A) = 0.3, P(B) = 0.4, and A, B are mutually exclusive, then P(A∪B) is:

A. 0.5

B. 0.7

C. 0.12

D. 0.1

Answer: Option B

Solution (By JKSSB Mock Tests)

Mutually exclusive → P(A∪B) = P(A) + P(B) = 0.3+0.4=0.7.

This question belongs to: Accountancy and Statistics Statistics

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Practice More Statistics Questions

Question #1

A frequency distribution is best described as:

A. A measure of the central value of a dataset

B. A graphical representation of data using bars

C. A method for calculating the range of data

D. A tabular arrangement showing the number of observations in each class interval

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Correct Answer: Option D

Explanation:
A frequency distribution organizes data into classes or intervals and displays the count (frequency) of observations falling within each class, summarizing the data's pattern.

This question belongs to: Accountancy and Statistics Statistics

Question #2

The time reversal test is satisfied by which of the following weighted index formulas?

A. Paasche

B. Laspeyres

C. Both A and C

D. Fisher

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Correct Answer: Option D

Explanation:
Only Fisher's index satisfies time reversal; L and P do not.

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Question #3

A box contains 5 defective and 15 non-defective items. Two items are drawn. The probability that both are non-defective is:

A. (15/20)²

B. 1 - (5/20)²

C. 21/38

D. 15/20 × 14/19 = 21/38

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Correct Answer: Option D

Explanation:
P(both non-defective) = (15/20)×(14/19) = 210/380 = 21/38.

This question belongs to: Accountancy and Statistics Statistics

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