In the reaction 2FeCl₃ + SnCl₂ → 2FeCl₂ + SnCl₄, which substance is reduced?
A. SnCl₄
B. FeCl₃
C. SnCl₂
D. FeCl₂
Answer: Option B
Solution (By JKSSB Mock Tests)
Fe in FeCl₃ goes from +3 to +2 in FeCl₂, gaining an electron – reduction. Sn in SnCl₂ goes from +2 to +4 in SnCl₄, losing electrons – oxidation. FeCl₃ is the oxidizing agent, SnCl₂ is the reducing agent.
Explanation:
Calorific value is the amount of heat energy produced on the complete combustion of 1 kg (or 1 m³ for gases) of a fuel. It is expressed in kJ/kg or kJ/m³. Hydrogen has the highest calorific value among common fuels, making it a highly efficient energy source.
Explanation:
In Fe₂O₃, oxygen has valency 2. Two Fe atoms combined with three O atoms: total negative charge = 6. For two Fe, total positive = 6, so each Fe has +3. Valency = 3 (ferric). In FeO, valency is 2 (ferrous).
Explanation:
Sodium lauryl sulfate (CH₃(CH₂)₁₁OSO₃Na) is a synthetic detergent with a sulfate group. Sodium stearate and potassium palmitate are soaps (carboxylate salts). Calcium oleate is soap scum.
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