In the reaction: 2PbO + C → 2Pb + CO₂, which substance is oxidized? MCQ with Answer and Explanation

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In the reaction: 2PbO + C → 2Pb + CO₂, which substance is oxidized?

A. Pb

B. CO₂

C. PbO

D. C

Answer: Option D

Solution (By JKSSB Mock Tests)

Oxidation is the gain of oxygen or loss of electrons. Here, Carbon (C) gains oxygen to form Carbon dioxide (CO₂), so Carbon is oxidized. Lead oxide (PbO) loses oxygen to form Lead (Pb), so PbO is reduced. This is a classic redox reaction where both processes occur simultaneously.

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Question #1

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Assertion (A): Radioactive decay is a nuclear process. Reason (R): It involves changes in the nucleus of an atom.

A. A is true but R is false.

B. Both A and R are true and R is the correct explanation of A.

C. A is false but R is true.

D. Both A and R are true but R is NOT the correct explanation of A.

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Correct Answer: Option B

Explanation:
Radioactive decay is a spontaneous process where an unstable atomic nucleus loses energy by emitting radiation. Since it involves the emission of particles (protons, neutrons, electrons) from the nucleus, it fundamentally alters the nucleus, making it a nuclear, not chemical, process.

This question belongs to: Science chemistry

Question #2

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The main ore of aluminium is:

A. Bauxite

B. Galena

C. Cinnabar

D. Haematite

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Correct Answer: Option A

Explanation:
Bauxite (Al₂O₃·2H₂O) is the principal ore of aluminium. Haematite is Fe₂O₃, galena is PbS, cinnabar is HgS. Bauxite is refined by Bayer's process to produce alumina, then electrolytically reduced (Hall-Héroult process).

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Question #3

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An element with atomic number 15 belongs to which group and period?

A. Group 15, Period 3

B. Group 15, Period 4

C. Group 5, Period 3

D. Group 3, Period 15

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Correct Answer: Option A

Explanation:
Atomic number 15 is phosphorus. Electronic configuration: 2, 8, 5. Number of shells = 3 (Period 3). Valence electrons = 5, so it is in group 15 (10+5) for p-block elements. Group 5 is for d-block. Thus Group 15, Period 3.

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