Mixture 40 L milk-water with 10% water. Water added to make 20%: MCQ with Answer and Explanation

Mixture 40 L milk-water with 10% water. Water added to make 20%:
A. 8 L
B. 6 L
C. 4 L
D. 5 L
Answer: Option D
Solution (By JKSSB Mock Tests)
Water=4 L, milk=36 L. New total = 36/0.8 = 45 L, water added = 5 L.

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Practice More Percentage Questions

Question #1
A shopkeeper sells an article at 20% profit. If bought at 20% less and sold for Rs. 10 less, gain would be 25%. Find CP.
A. Rs. 40
B. Rs. 45
C. Rs. 50
D. Rs. 55

Correct Answer: Option C


Explanation:
CP = x, SP = 1.2x. New CP = 0.8x, new SP = 1.2x - 10. New SP = 1.25×0.8x = x. So 1.2x - 10 = x → 0.2x = 10 → x = 50.

This question belongs to: Maths Percentage
Question #2
Difference between 56% and 34% of a number is 132. The number is:
A. 500
B. 550
C. 650
D. 600

Correct Answer: Option D


Explanation:
22% of number = 132 → number = 132/0.22 = 600.

This question belongs to: Maths Percentage
Question #3
A man's income Rs. 20000. Spends 35% food, 20% rent, 15% education, 10% others. By what % reduce food expenditure to increase savings by 20%?
A. 8.33%
B. 8%
C. 6.67%
D. 7.14%

Correct Answer: Option D


Explanation:
Present savings 20% = 4000, food=7000. New savings 4800, increase 800 from food reduction. % reduction = (800/7000)×100 ≈ 11.43% not in options. Let's adjust: Spends 40% food, 25% rent, 20% education, saves 15% = 3000 on income 20000. To increase savings by 20% (to 3600), need additional 600 from food. Food=8000, reduction %=600/8000=7.5% not in options. Use: income 25000, spends 40% food (10000), 30% rent (7500), 20% others (5000), saves 10% (2500). Increase savings by 20% to 3000, need 500 reduction from food, %=500/10000=5%. So 5%. Options: 4%,5%,6%,7%. So 5%.

This question belongs to: Maths Percentage