If a dataset has values ranging from 10 to 95 and you decide to use a class width of 10, how many classes would be needed for an exclusive frequency distribution?
Explanation:
Range = 95 - 10 = 85. Number of classes = Range / Class width = 85 / 10 = 8.5, rounded up to 9 classes to cover the entire data range without gaps.
Explanation:
Mutually exclusive events cannot occur together, so their intersection probability is zero, removing the subtraction term in the general addition theorem.
No comments yet. Be the first to start the discussion!