Ratio of present ages of A and B is 7:5. After 10 years, the ratio becomes 8:8. Present age of A is? MCQ with Answer and Explanation

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Ratio of present ages of A and B is 7:5. After 10 years, the ratio becomes 8:8. Present age of A is?

A. 266 years

B. 138 years

C. 133 years

D. 127 years

Answer: Option C

Solution (By JKSSB Mock Tests)

Let ages 7k and 5k. Then (7k + 10)/(5k + 10) = 8/8. Solving gives k ≈ 19, age of A = 7*19 = 133.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Two numbers are in the ratio 12:10 and their sum is 753. Find the numbers.

A. 429 and 320

B. 816 and 680

C. 408 and 340

D. 396 and 345

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Correct Answer: Option C

Explanation:
Numbers = 12k and 10k. 12k + 10k = 753 ⇒ k = 34. Thus, numbers are 408 and 340.

This question belongs to: Maths Ratio and Proportion

Question #2

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Milk and water are in ratio 7:6 in a 528 L mixture. Quantity of milk?

A. 334 L

B. 284 L

C. 244 L

D. 568 L

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Correct Answer: Option B

Explanation:
Total parts = 13. Milk = [7 / (7+6)] × 528 = 284 L.

This question belongs to: Maths Ratio and Proportion

Question #3

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If a:b = 5:8 and b:c = 8:11, then a:b:c = ?

A. 5:9:11

B. 5:8:11

C. 10:16:22

D. 4:8:12

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Correct Answer: Option B

Explanation:
Combine ratios: a:b = 5:8, b:c = 8:11 ⇒ a:b:c = 5:8:11.

This question belongs to: Maths Ratio and Proportion

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