Ratio of present ages of A and B is 7:5. After 10 years, the ratio becomes 8:8. Present age of A is? MCQ with Answer and Explanation

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Ratio of present ages of A and B is 7:5. After 10 years, the ratio becomes 8:8. Present age of A is?

A. 266 years

B. 127 years

C. 138 years

D. 133 years

Answer: Option D

Solution (By JKSSB Mock Tests)

Let ages 7k and 5k. Then (7k + 10)/(5k + 10) = 8/8. Solving gives k ≈ 19, age of A = 7*19 = 133.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Two numbers are in the ratio 12:5 and their sum is 771. Find the numbers.

A. 540 and 225

B. 1080 and 450

C. 523 and 234

D. 556 and 206

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Correct Answer: Option A

Explanation:
Numbers = 12k and 5k. 12k + 5k = 771 ⇒ k = 45. Thus, numbers are 540 and 225.

This question belongs to: Maths Ratio and Proportion

Question #2

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Find the mean proportional between 16 and 39.

A. 55

B. 48

C. 24

D. 27

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Correct Answer: Option C

Explanation:
Mean proportional = √(16 × 39) = √(624) = 24.

This question belongs to: Maths Ratio and Proportion

Question #3

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Ratio of present ages of A and B is 4:8. After 8 years, the ratio becomes 6:10. Present age of A is?

A. 49 years

B. 88 years

C. 37 years

D. 44 years

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Correct Answer: Option D

Explanation:
Let ages 4k and 8k. Then (4k + 8)/(8k + 8) = 6/10. Solving gives k ≈ 11, age of A = 4*11 = 44.

This question belongs to: Maths Ratio and Proportion

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