Ratio of present ages of A and B is 7:5. After 7 years, the ratio becomes 10:8. Present age of A is? MCQ with Answer and Explanation

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Ratio of present ages of A and B is 7:5. After 7 years, the ratio becomes 10:8. Present age of A is?

A. 126 years

B. 123 years

C. 252 years

D. 131 years

Answer: Option A

Solution (By JKSSB Mock Tests)

Let ages 7k and 5k. Then (7k + 7)/(5k + 7) = 10/8. Solving gives k ≈ 18, age of A = 7*18 = 126.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Two numbers are in the ratio 6:5 and their sum is 616. Find the numbers.

A. 672 and 560

B. 357 and 269

C. 328 and 295

D. 336 and 280

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Correct Answer: Option D

Explanation:
Numbers = 6k and 5k. 6k + 5k = 616 ⇒ k = 56. Thus, numbers are 336 and 280.

This question belongs to: Maths Ratio and Proportion

Question #2

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Find the mean proportional between 16 and 39.

A. 24

B. 55

C. 27

D. 48

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Correct Answer: Option A

Explanation:
Mean proportional = √(16 × 39) = √(624) = 24.

This question belongs to: Maths Ratio and Proportion

Question #3

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Ratio of present ages of A and B is 7:8. After 11 years, the ratio becomes 10:10. Present age of A is?

A. 156 years

B. 161 years

C. 166 years

D. 322 years

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Correct Answer: Option B

Explanation:
Let ages 7k and 8k. Then (7k + 11)/(8k + 11) = 10/10. Solving gives k ≈ 23, age of A = 7*23 = 161.

This question belongs to: Maths Ratio and Proportion

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