Ratio of present ages of A and B is 7:8. After 10 years, the ratio becomes 9:10. Present age of A is? MCQ with Answer and Explanation

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Ratio of present ages of A and B is 7:8. After 10 years, the ratio becomes 9:10. Present age of A is?

A. 152 years

B. 147 years

C. 143 years

D. 294 years

Answer: Option B

Solution (By JKSSB Mock Tests)

Let ages 7k and 8k. Then (7k + 10)/(8k + 10) = 9/10. Solving gives k ≈ 21, age of A = 7*21 = 147.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Ratio of present ages of A and B is 5:6. After 9 years, the ratio becomes 7:7. Present age of A is?

A. 200 years

B. 95 years

C. 100 years

D. 105 years

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Correct Answer: Option C

Explanation:
Let ages 5k and 6k. Then (5k + 9)/(6k + 9) = 7/7. Solving gives k ≈ 20, age of A = 5*20 = 100.

This question belongs to: Maths Ratio and Proportion

Question #2

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If a:b = 5:7 and b:c = 7:5, then a:b:c = ?

A. 5:8:5

B. 10:14:10

C. 4:7:6

D. 5:7:5

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Correct Answer: Option D

Explanation:
Combine ratios: a:b = 5:7, b:c = 7:5 ⇒ a:b:c = 5:7:5.

This question belongs to: Maths Ratio and Proportion

Question #3

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If a:b = 7:7 and b:c = 7:4, then a:b:c = ?

A. 7:7:4

B. 7:8:4

C. 6:7:5

D. 14:14:8

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Correct Answer: Option A

Explanation:
Combine ratios: a:b = 7:7, b:c = 7:4 ⇒ a:b:c = 7:7:4.

This question belongs to: Maths Ratio and Proportion

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