Ratio of present ages of A and B is 7:8. After 10 years, the ratio becomes 9:10. Present age of A is? MCQ with Answer and Explanation

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Ratio of present ages of A and B is 7:8. After 10 years, the ratio becomes 9:10. Present age of A is?

A. 143 years

B. 294 years

C. 147 years

D. 152 years

Answer: Option C

Solution (By JKSSB Mock Tests)

Let ages 7k and 8k. Then (7k + 10)/(8k + 10) = 9/10. Solving gives k ≈ 21, age of A = 7*21 = 147.

This question belongs to: Maths Ratio and Proportion

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Question #1

If a:b = 7:7 and b:c = 7:9, then a:b:c = ?

A. 7:7:9

B. 7:8:9

C. 14:14:18

D. 6:7:10

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Correct Answer: Option A

Explanation:
Combine ratios: a:b = 7:7, b:c = 7:9 ⇒ a:b:c = 7:7:9.

This question belongs to: Maths Ratio and Proportion

Question #2

If a:b = 2:7 and b:c = 7:12, then a:b:c = ?

A. 1:7:13

B. 4:14:24

C. 2:8:12

D. 2:7:12

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Correct Answer: Option D

Explanation:
Combine ratios: a:b = 2:7, b:c = 7:12 ⇒ a:b:c = 2:7:12.

This question belongs to: Maths Ratio and Proportion

Question #3

Two numbers are in the ratio 12:5 and their sum is 771. Find the numbers.

A. 523 and 234

B. 540 and 225

C. 556 and 206

D. 1080 and 450

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Correct Answer: Option B

Explanation:
Numbers = 12k and 5k. 12k + 5k = 771 ⇒ k = 45. Thus, numbers are 540 and 225.

This question belongs to: Maths Ratio and Proportion

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