Ratio of present ages of A and B is 7:8. After 10 years, the ratio becomes 9:10. Present age of A is? MCQ with Answer and Explanation

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Ratio of present ages of A and B is 7:8. After 10 years, the ratio becomes 9:10. Present age of A is?

A. 143 years

B. 152 years

C. 294 years

D. 147 years

Answer: Option D

Solution (By JKSSB Mock Tests)

Let ages 7k and 8k. Then (7k + 10)/(8k + 10) = 9/10. Solving gives k ≈ 21, age of A = 7*21 = 147.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Milk and water are in ratio 4:3 in a 255 L mixture. Quantity of milk?

A. 191 L

B. 290 L

C. 145 L

D. 110 L

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Correct Answer: Option C

Explanation:
Total parts = 7. Milk = [4 / (4+3)] × 255 = 145 L.

This question belongs to: Maths Ratio and Proportion

Question #2

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Milk and water are in ratio 6:6 in a 413 L mixture. Quantity of milk?

A. 245 L

B. 412 L

C. 206 L

D. 207 L

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Correct Answer: Option C

Explanation:
Total parts = 12. Milk = [6 / (6+6)] × 413 = 206 L.

This question belongs to: Maths Ratio and Proportion

Question #3

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If a:b = 3:8 and b:c = 8:4, then a:b:c = ?

A. 6:16:8

B. 3:8:4

C. 2:8:5

D. 3:9:4

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Correct Answer: Option B

Explanation:
Combine ratios: a:b = 3:8, b:c = 8:4 ⇒ a:b:c = 3:8:4.

This question belongs to: Maths Ratio and Proportion

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