The catalyst used in the Contact process for manufacturing sulfuric acid is: MCQ with Answer and Explanation

The catalyst used in the Contact process for manufacturing sulfuric acid is:
A. Manganese dioxide
B. Iron
C. Nickel
D. Vanadium pentoxide (V₂O₅)
Answer: Option D
Solution (By JKSSB Mock Tests)
The Contact process involves the oxidation of SO₂ to SO₃. The catalyst used for this step is Vanadium pentoxide (V₂O₅) or sometimes platinized asbestos. Iron is used in the Haber process, and Nickel is commonly used in the hydrogenation of vegetable oils.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More chemistry Questions

Question #1
The main raw material for the manufacture of cement is:
A. Sand and clay
B. Limestone and gypsum
C. Gypsum and sand
D. Limestone and clay

Correct Answer: Option D


Explanation:
Portland cement is primarily made by heating a mixture of limestone (calcium carbonate) and clay (aluminosilicates) in a kiln at about 1450°C to form clinker. A small amount of gypsum is then added to the clinker to control the setting time, but limestone and clay are the main raw materials.

This question belongs to: Science chemistry
Question #2
Which gas will diffuse fastest under identical conditions?
A. N₂
B. NH₃
C. CO₂
D. O₂

Correct Answer: Option B


Explanation:
Rate of diffusion is inversely proportional to the square root of molar mass (Graham's law). Lighter gases diffuse faster. Molar masses: NH₃ = 17, N₂ = 28, O₂ = 32, CO₂ = 44 g/mol. Therefore NH₃ has the lowest molar mass and diffuses fastest. This law also explains why the smell of perfume spreads quickly. NH₃ is lighter than air and would rise.

This question belongs to: Science chemistry
Question #3
A gas at STP occupies 22.4 L. If pressure is doubled and temperature is doubled, the volume becomes:
A. 5.6 L
B. 11.2 L
C. 44.8 L
D. 22.4 L

Correct Answer: Option D


Explanation:
Combined gas law: P₁V₁/T₁ = P₂V₂/T₂. Given P₂ = 2P₁, T₂ = 2T₁. So V₂ = V₁ × (P₁/P₂) × (T₂/T₁) = 22.4 × (1/2) × (2/1) = 22.4 L. Pressure increase tries to halve volume, temperature increase tries to double volume; they cancel out. So volume remains unchanged. This assumes ideal behavior.

This question belongs to: Science chemistry