The difference between simple interest and compound interest on a certain sum of money for 3 years at 10% per annum is Rs. 620. Find the sum. MCQ with Answer and Explanation

The difference between simple interest and compound interest on a certain sum of money for 3 years at 10% per annum is Rs. 620. Find the sum.
A. Rs. 20000
B. Rs. 24000
C. Rs. 18000
D. Rs. 22000
Answer: Option A
Solution (By JKSSB Mock Tests)
Difference for 3 years = P * (R/100)^2 * (3 + R/100) => 620 = P * (10/100)^2 * (3 + 10/100) => 620 = P * (1/100) * (3.1) => 620 = P * 0.031 => P = 620 / 0.031 = Rs. 20000.

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Practice More Compound Interest Questions

Question #1
The simple interest on a sum for 2 years at 6% is Rs. 480. The compound interest on the same sum for 2 years at 6% is:
A. Rs. 499.20
B. Rs. 494.40
C. Rs. 504.00
D. Rs. 508.80

Correct Answer: Option B


Explanation:
P = 48000/(6×2) = 4000. CI = 4000[(1.06)² − 1] = 4000 × 0.1236 = Rs. 494.40.

This question belongs to: Maths Compound Interest
Question #2
The simple interest on a certain sum for 2 years at 5% is Rs. 200. The compound interest on the same sum for the same period and rate is:
A. Rs. 200
B. Rs. 210
C. Rs. 205
D. Rs. 215

Correct Answer: Option C


Explanation:
SI = P × 5 × 2/100 = 0.1P = 200 ⇒ P = 2000. CI = P[(1.05)² − 1] = 2000 × 0.1025 = Rs. 205.

This question belongs to: Maths Compound Interest
Question #3
A sum of money placed at compound interest doubles itself in 4 years. In how many years will it amount to 8 times itself?
A. 12 years
B. 8 years
C. 16 years
D. 10 years

Correct Answer: Option A


Explanation:
2 times in 4 years, 8 = 2³ ⇒ 4 × 3 = 12 years.

This question belongs to: Maths Compound Interest