The oil drop experiment to determine the charge of an electron was performed by: MCQ with Answer and Explanation

The oil drop experiment to determine the charge of an electron was performed by:
A. J.J. Thomson
B. Robert Millikan
C. James Chadwick
D. Ernest Rutherford
Answer: Option B
Solution (By JKSSB Mock Tests)
Robert Millikan performed the oil drop experiment in 1909. By observing charged oil droplets in an electric field, he accurately determined the elementary charge of an electron (e = 1.6 × 10⁻¹⁹ C). This, combined with Thomson's e/m ratio, allowed calculating the electron's mass.

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Practice More chemistry Questions

Question #1
Which of the following is an example of a physical change?
A. Rusting of iron
B. Burning of magnesium ribbon
C. Melting of wax
D. Digestion of food

Correct Answer: Option C


Explanation:
Melting of wax is a physical change because it involves only a change in state from solid to liquid without altering the chemical composition. The wax remains the same hydrocarbon mixture. In contrast, rusting of iron (Fe₂O₃·xH₂O formation), burning of magnesium (MgO formation), and digestion of food (enzymatic breakdown into simpler molecules) are chemical changes where new substances are formed. Physical changes are reversible, while most chemical changes are irreversible. Exam tip: Remember, changes of state (melting, boiling, condensation) are physical changes unless a chemical reaction accompanies them.

This question belongs to: Science chemistry
Question #2
Diamond is not a good conductor of electricity because:
A. It has a layered structure.
B. All valence electrons are involved in covalent bonds.
C. It is very hard.
D. It is made of carbon.

Correct Answer: Option B


Explanation:
In diamond, each carbon atom is sp³ hybridized and forms four strong covalent bonds, utilizing all four valence electrons. No free electrons are available for conduction. Graphite has free delocalized electrons per carbon, making it a conductor.

This question belongs to: Science chemistry
Question #3
A solution turns phenolphthalein pink. Which of the following could it be?
A. Vinegar
B. Soap solution
C. Lemon juice
D. Hydrochloric acid

Correct Answer: Option B


Explanation:
Soap solution is basic, pH > 8.3, so it turns phenolphthalein pink. Lemon juice (citric acid) and vinegar (acetic acid) are acidic, pH < 7, phenolphthalein remains colorless. Hydrochloric acid is strongly acidic, colorless. Phenolphthalein indicator is colorless in acidic and neutral, pink in alkaline solutions. It is used in titrations.

This question belongs to: Science chemistry