The population of a city increases at the rate of 5% annually. If the present population is 185220, what was its population 3 years ago? MCQ with Answer and Explanation

Question

The population of a city increases at the rate of 5% annually. If the present population is 185220, what was its population 3 years ago?

A. 170000

B. 180000

C. 150000

D. 160000

Answer: Option D

Solution (By JKSSB Mock Tests)

Population 3 years ago = 185220 / (1 + 5/100)^3 = 185220 / (21/20)^3 = 185220 * 8000 / 9261 = 20 * 8000 = 160000.

This question belongs to: Maths Compound Interest

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Question #1

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A machine depreciates at 5% per annum. Its present value is Rs. 5415. What was its value 2 years ago?

A. Rs. 6200

B. Rs. 6000

C. Rs. 5800

D. Rs. 6400

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Correct Answer: Option B

Explanation:
Value 2 years ago = 5415 / (0.95)² = 5415 / 0.9025 = 6000.

This question belongs to: Maths Compound Interest

Question #2

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The compound interest on Rs. 14000 at 10% per annum for 2 years is:

A. Rs. 3080

B. Rs. 3100

C. Rs. 2940

D. Rs. 2800

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Correct Answer: Option C

Explanation:
A = 14000 × (1.1)² = 14000 × 1.21 = 16940, CI = 16940 − 14000 = Rs. 2940.

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Question #3

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The compound interest on Rs. 6000 at 5% per annum for 2 years is:

A. Rs. 630

B. Rs. 615

C. Rs. 600

D. Rs. 645

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Correct Answer: Option B

Explanation:
A = 6000 × 1.1025 = 6615, CI = 6615 − 6000 = Rs. 615.

This question belongs to: Maths Compound Interest

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