The population of a small community grows by 10% in the first year and decreases by 10% in the second year. If the population at the end of 2 years is 39600, find the original population. MCQ with Answer and Explanation

The population of a small community grows by 10% in the first year and decreases by 10% in the second year. If the population at the end of 2 years is 39600, find the original population.
A. Rs. 40000
B. Rs. 42000
C. Rs. 38000
D. Rs. 44000
Answer: Option A
Solution (By JKSSB Mock Tests)
Net change over 2 years = +10 - 10 - (1010)/100 = -1% (decrease). So, 99% of original population = 39600 => Original population = 39600 / 0.99 = 40000.

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Practice More Compound Interest Questions

Question #1
A sum of money at compound interest becomes 4 times in 2 years. In how many years will it become 16 times?
A. 5 years
B. 4 years
C. 3 years
D. 6 years

Correct Answer: Option B


Explanation:
4 times in 2 years; 16 = 4², so time = 2 × 2 = 4 years.

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Question #2
What sum will amount to Rs. 11664 in 2 years at 8% compound interest?
A. Rs. 10500
B. Rs. 9500
C. Rs. 10000
D. Rs. 11000

Correct Answer: Option C


Explanation:
P = 11664 / (1.08)² = 11664 / 1.1664 = 10000.

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Question #3
A sum becomes Rs. 2315.25 in 2 years at 5% compound interest. Find the sum.
A. Rs. 2000
B. Rs. 2300
C. Rs. 2200
D. Rs. 2100

Correct Answer: Option D


Explanation:
P = 2315.25 / (1.05)² = 2315.25 / 1.1025 = 2100.

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