The population of a town increases by 10% annually. If the current population is 12,100, what was the population two years ago? MCQ with Answer and Explanation

The population of a town increases by 10% annually. If the current population is 12,100, what was the population two years ago?
A. 12,000
B. 9,000
C. 11,000
D. 10,000
Answer: Option D
Solution (By JKSSB Mock Tests)
Let the population two years ago be P. P * (110 / 100) * (110 / 100) = 12100. P * 1.21 = 12100 implies P = 10000.

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Practice More Percentage Questions

Question #1
Price reduced 20%, enables buying 5 kg more for Rs. 120. Reduced price/kg:
A. Rs. 5
B. Rs. 4.8
C. Rs. 4
D. Rs. 3.2

Correct Answer: Option D


Explanation:
Original x, xy=120. New 0.8x(y+5)=120 → 0.8×120 + 4x =120 → 96+4x=120 → 4x=24 → x=6, reduced 4.8? Wait: original x=6, reduced price = 0.8*6=4.8, option C. Check: original 6 per kg, 20 kg for 120. Reduced 4.8, buys 25 kg for 120, 5 kg more. So reduced price = 4.8. Option C. So answer C.

This question belongs to: Maths Percentage
Question #2
130% of 130 is:
A. 149
B. 159
C. 169
D. 179

Correct Answer: Option C


Explanation:
1.3 × 130 = 169.

This question belongs to: Maths Percentage
Question #3
Ratio 2:5, second part expressed as percentage of total is:
A. 65.5%
B. 70%
C. 71.43%
D. 60%

Correct Answer: Option C


Explanation:
Second part = 5/(2+5) × 100 ≈ 71.43%.

This question belongs to: Maths Percentage