The population of a town increases by 15% in the first year and decreases by 10% in the second year. If the population at the end of second year is 10350, what was the population at the beginning? MCQ with Answer and Explanation

The population of a town increases by 15% in the first year and decreases by 10% in the second year. If the population at the end of second year is 10350, what was the population at the beginning?
A. 9000
B. 10500
C. 9500
D. 10000
Answer: Option D
Solution (By JKSSB Mock Tests)
Net multiplier = 1.15 × 0.9 = 1.035. Population = 10350/1.035 = 10000.

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Practice More Percentage Questions

Question #1
If the price of rice decreases by 20%, by what percentage can consumption be increased without changing expenditure?
A. 25%
B. 30%
C. 33.33%
D. 20%

Correct Answer: Option A


Explanation:
Required increase = (R / (100 - R)) * 100. (20 / 80) * 100 = 25%.

This question belongs to: Maths Percentage
Question #2
In an election, 25% of the votes were invalid. The winner got 56% of the valid votes and defeated the other candidate by 1800 votes. What was the total number of votes?
A. 18000
B. 15000
C. 20000
D. 22000

Correct Answer: Option C


Explanation:
Valid votes V = 0.75T. Winner = 0.56V, loser = 0.44V, margin = 0.12V = 1800 → V=15000 → T=20000.

This question belongs to: Maths Percentage
Question #3
A 20% reduction in the price of sugar enables a man to buy 2 kg more for Rs. 60. The original price per kg is:
A. Rs. 5
B. Rs. 7.5
C. Rs. 8
D. Rs. 6

Correct Answer: Option B


Explanation:
Let original price x. 60/x + 2 = 60/(0.8x). Multiply: 60+2x = 75 → 2x=15 → x=7.5.

This question belongs to: Maths Percentage