The population of a town increases by 15% in the first year and decreases by 10% in the second year. If the population at the end of second year is 10350, what was the population at the beginning? MCQ with Answer and Explanation

The population of a town increases by 15% in the first year and decreases by 10% in the second year. If the population at the end of second year is 10350, what was the population at the beginning?
A. 9500
B. 10000
C. 10500
D. 9000
Answer: Option B
Solution (By JKSSB Mock Tests)
Net multiplier = 1.15 × 0.9 = 1.035. Population = 10350/1.035 = 10000.

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Practice More Percentage Questions

Question #1
If A is 25% more than B, then B is what percentage less than A?
A. 15%
B. 20%
C. 25%
D. 30%

Correct Answer: Option B


Explanation:
Formula: (R / (100 + R)) * 100. Here R = 25. (25 / 125) * 100 = (1 / 5) * 100 = 20%.

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Question #2
Value of a scooter depreciates 8% per year. Price 50,000, after 1 year value is:
A. 48,000
B. 46,000
C. 47,000
D. 45,000

Correct Answer: Option B


Explanation:
Value = 50,000 × 0.92 = 46,000.

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Question #3
In an examination, 70% passed in English, 65% in Maths and 15% failed in both subjects. If 300 students passed in both, total number of students was:
A. 650
B. 600
C. 500
D. 550

Correct Answer: Option B


Explanation:
Failed Eng=30%, Maths=35%. Passed both = 100 - (30+35-15) = 50%. 50% of total = 300 → total = 600.

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