The population of a town is 10,000. It increases by 10% annually. What will be the population after 2 years? MCQ with Answer and Explanation

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The population of a town is 10,000. It increases by 10% annually. What will be the population after 2 years?

A. 12100

B. 12000

C. 12200

D. 11000

Answer: Option A

Solution (By JKSSB Mock Tests)

Population = P * (1 + R/100)^t = 10000 * (1.10)^2 = 10000 * 1.21 = 12100.

This question belongs to: Maths Percentage

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Practice More Percentage Questions

Question #1

A number increased by 35% becomes 270. The number is:

A. 190

B. 210

C. 180

D. 200

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Correct Answer: Option D

Explanation:
1.35x = 270 → x = 200.

This question belongs to: Maths Percentage

Question #2

A number decreased by 10% becomes 90. The number is:

A. 110

B. 95

C. 100

D. 105

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Correct Answer: Option C

Explanation:
0.9x = 90 → x = 100.

This question belongs to: Maths Percentage

Question #3

Population 15000, first year +10%, second year -10%. Population after 2 years:

A. 14900

B. 14850

C. 15000

D. 15100

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Correct Answer: Option B

Explanation:
15000×1.1×0.9 = 14850.

This question belongs to: Maths Percentage

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