The present population of a town is 10,890. If it increases by 10% yearly, what was its population 2 years ago? MCQ with Answer and Explanation

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The present population of a town is 10,890. If it increases by 10% yearly, what was its population 2 years ago?

A. 9000

B. 10000

C. 8000

D. 9500

Answer: Option A

Solution (By JKSSB Mock Tests)

P_past = P_present / (1 + R/100)^2 = 10890 / (1.10)^2 = 10890 / 1.21 = 9000.

This question belongs to: Maths Percentage

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Practice More Percentage Questions

Question #1

If 40% of a number is 80, the number is:

A. 100

B. 250

C. 200

D. 150

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Correct Answer: Option C

Explanation:
0.4x = 80 → x = 200.

This question belongs to: Maths Percentage

Question #2

A student scored 20% marks and failed by 36 marks. Another student scored 30% marks and got 24 marks more than the passing marks. Find the passing marks.

A. 156

B. 160

C. 140

D. 180

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Correct Answer: Option A

Explanation:
0.2M + 36 = 0.3M - 24 → 0.1M = 60 → M = 600. Passing marks = 0.2×600+36 = 156.

This question belongs to: Maths Percentage

Question #3

A number is increased by 15% and then decreased by 15%. If the resulting number is 782, what was the original number?

A. 800

B. 820

C. 780

D. 750

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Correct Answer: Option A

Explanation:
1.15 × 0.85 = 0.9775. 0.9775x = 782 → x = 782/0.9775 = 800.

This question belongs to: Maths Percentage

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