The present population of a town is 10,890. If it increases by 10% yearly, what was its population 2 years ago? MCQ with Answer and Explanation

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The present population of a town is 10,890. If it increases by 10% yearly, what was its population 2 years ago?

A. 8000

B. 9500

C. 9000

D. 10000

Answer: Option C

Solution (By JKSSB Mock Tests)

P_past = P_present / (1 + R/100)^2 = 10890 / (1.10)^2 = 10890 / 1.21 = 9000.

This question belongs to: Maths Percentage

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Weight reduced from 90 kg to 81 kg. Percentage decrease:

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Correct Answer: Option C

Explanation:
Decrease = 9 kg, (9/90)×100 = 10%.

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Question #2

What is 15% of 60?

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15% of 60 = (15 / 100) * 60 = 9.

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Question #3

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Correct Answer: Option B

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