The present population of a town is 10,890. If it increases by 10% yearly, what was its population 2 years ago? MCQ with Answer and Explanation

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The present population of a town is 10,890. If it increases by 10% yearly, what was its population 2 years ago?

A. 10000

B. 9000

C. 8000

D. 9500

Answer: Option B

Solution (By JKSSB Mock Tests)

P_past = P_present / (1 + R/100)^2 = 10890 / (1.10)^2 = 10890 / 1.21 = 9000.

This question belongs to: Maths Percentage

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Question #1

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Radius of a circle increased by 100%. Percentage increase in area:

A. 300%

B. 100%

C. 400%

D. 200%

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Correct Answer: Option A

Explanation:
Area proportional to radius². New radius 2r, area 4 times, increase = 300%.

This question belongs to: Maths Percentage

Question #2

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The marked price of an article is 50% above its cost price. The shopkeeper allows a discount of 20% and earns a profit of Rs. 60. Find the cost price.

A. Rs. 300

B. Rs. 350

C. Rs. 250

D. Rs. 200

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Correct Answer: Option A

Explanation:
CP=x, MP=1.5x, SP=1.5x×0.8=1.2x. Profit = 0.2x = 60 → x=300.

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Question #3

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Difference between 44% and 32% of a number is 84. The number is:

A. 600

B. 750

C. 650

D. 700

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Correct Answer: Option D

Explanation:
12% of number = 84 → number = 84/0.12 = 700.

This question belongs to: Maths Percentage

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