The process of converting vegetable oils to solid fats (vanaspati) involves: MCQ with Answer and Explanation

The process of converting vegetable oils to solid fats (vanaspati) involves:
A. Hydrogenation
B. Saponification
C. Esterification
D. Fermentation
Answer: Option A
Solution (By JKSSB Mock Tests)
Hydrogenation adds hydrogen to unsaturated vegetable oils in the presence of nickel catalyst at about 150°C, converting liquid oils (C=C bonds) to solid fats (vanaspati ghee) with higher melting points. Saponification makes soap. Esterification forms esters. Fermentation produces alcohol. Partial hydrogenation can produce trans fats, which are harmful. Complete hydrogenation yields saturated fats.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More chemistry Questions

Question #1
Which of the following elements is a metalloid?
A. Germanium
B. Chlorine
C. Aluminium
D. Sodium

Correct Answer: Option A


Explanation:
Germanium (Ge) is a metalloid, exhibiting properties of both metals and non-metals. It is a semiconductor used in transistors. Sodium and aluminium are metals. Chlorine is a non-metal. Metalloids are located along the zigzag line in the p-block.

This question belongs to: Science chemistry
Question #2
The chemical name of washing soda is:
A. Sodium hydroxide
B. Sodium chloride
C. Sodium bicarbonate
D. Sodium carbonate decahydrate

Correct Answer: Option D


Explanation:
Washing soda is sodium carbonate decahydrate, with the chemical formula Na₂CO₃·10H₂O. Sodium bicarbonate is baking soda (NaHCO₃). Sodium hydroxide is caustic soda (NaOH), and sodium chloride is common table salt (NaCl). Washing soda is used for cleaning and water softening.

This question belongs to: Science chemistry
Question #3
The element with highest ionization energy in the second period is:
A. Neon
B. Fluorine
C. Lithium
D. Beryllium

Correct Answer: Option A


Explanation:
Ionization energy generally increases across a period due to increasing nuclear charge. Neon (noble gas) has the highest ionization energy in period 2 because of its stable filled octet (2s²2p⁶). Removing an electron requires enormous energy. Fluorine is next highest. Lithium has lowest. Noble gases have very high IE values, making them inert.

This question belongs to: Science chemistry