The rate of effusion of two gases A and B are in the ratio 1:2. If molar mass of A is 64 g/mol, molar mass of B is:

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Graham's law: r₁/r₂ = √(M₂/M₁). Given rA/rB = 1/2, so √(MB/MA) = 1/2. Squaring: MB/MA = 1/4 => MB = MA/4 = 64/4 = 16 g/mol. B is lighter and diffuses faster. Logical check: rate inversely proportional to square root of molar mass; if rate is double, mass is quarter. Answer is 16.

The rate of effusion of two gases A and B are in the ratio 1:2. If molar mass of A is 64 g/mol, molar mass of B is: MCQ with Answer and Explanation

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