Three students A,B,C solve a problem. Probabilities 1/2, 2/3, 3/4. Probability that exactly two of them solve it is:
A. 7/24
B. 13/24
C. 1/4
D. 11/24
Answer: Option D
Solution (By JKSSB Mock Tests)
P(AB'C) = 1/2 * 1/3 * 3/4 = 3/24; P(AB'C)? Let's compute exactly two: A and B not C: 1/2*2/3*1/4=2/24; A not B C: 1/2*1/3*3/4=3/24; not A B C: 1/2*2/3*3/4=6/24. Sum = 11/24.
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