Two numbers are in ratio 11:6. Their difference is 58. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 11:6. Their difference is 58. What is their sum?

A. 136

B. 391

C. 310

D. 272

Answer: Option D

Solution (By JKSSB Mock Tests)

Numbers 11k, 6k. Difference |11-6|k = 58 ⇒ k = 11. Sum = (11+6)k ≈ 272.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1

Find the mean proportional between 26 and 77.

A. 88

B. 47

C. 103

D. 44

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Correct Answer: Option D

Explanation:
Mean proportional = √(26 × 77) = √(2002) = 44.

This question belongs to: Maths Ratio and Proportion

Question #2

Two numbers are in the ratio 14:6 and their sum is 644. Find the numbers.

A. 448 and 192

B. 433 and 198

C. 896 and 384

D. 462 and 176

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Correct Answer: Option A

Explanation:
Numbers = 14k and 6k. 14k + 6k = 644 ⇒ k = 32. Thus, numbers are 448 and 192.

This question belongs to: Maths Ratio and Proportion

Question #3

Two numbers are in ratio 6:4. Their difference is 103. What is their sum?

A. 558

B. 500

C. 250

D. 617

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Correct Answer: Option B

Explanation:
Numbers 6k, 4k. Difference |6-4|k = 103 ⇒ k = 51. Sum = (6+4)k ≈ 500.

This question belongs to: Maths Ratio and Proportion

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