Two numbers are in ratio 11:6. Their difference is 58. What is their sum? MCQ with Answer and Explanation

Question

Share Report Error

Two numbers are in ratio 11:6. Their difference is 58. What is their sum?

A. 391

B. 272

C. 136

D. 310

Answer: Option B

Solution (By JKSSB Mock Tests)

Numbers 11k, 6k. Difference |11-6|k = 58 ⇒ k = 11. Sum = (11+6)k ≈ 272.

This question belongs to: Maths Ratio and Proportion

Request complete Subject PDF

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Ratio and Proportion Questions

Question #1

Share Report

Ratio of present ages of A and B is 7:6. After 11 years, the ratio becomes 9:9. Present age of A is?

A. 98 years

B. 103 years

C. 95 years

D. 196 years

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option A

Explanation:
Let ages 7k and 6k. Then (7k + 11)/(6k + 11) = 9/9. Solving gives k ≈ 14, age of A = 7*14 = 98.

This question belongs to: Maths Ratio and Proportion

Question #2

Share Report

Ratio of present ages of A and B is 6:5. After 5 years, the ratio becomes 7:6. Present age of A is?

A. 59 years

B. 48 years

C. 54 years

D. 108 years

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option C

Explanation:
Let ages 6k and 5k. Then (6k + 5)/(5k + 5) = 7/6. Solving gives k ≈ 9, age of A = 6*9 = 54.

This question belongs to: Maths Ratio and Proportion

Question #3

Share Report

If a:b = 7:7 and b:c = 7:4, then a:b:c = ?

A. 7:8:4

B. 7:7:4

C. 14:14:8

D. 6:7:5

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option B

Explanation:
Combine ratios: a:b = 7:7, b:c = 7:4 ⇒ a:b:c = 7:7:4.

This question belongs to: Maths Ratio and Proportion

Explore All Ratio and Proportion MCQs